(x^2+7x+49)=0

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Solution for (x^2+7x+49)=0 equation:


Simplifying
(x2 + 7x + 49) = 0

Reorder the terms:
(49 + 7x + x2) = 0

Remove parenthesis around (49 + 7x + x2)
49 + 7x + x2 = 0

Solving
49 + 7x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-49' to each side of the equation.
49 + 7x + -49 + x2 = 0 + -49

Reorder the terms:
49 + -49 + 7x + x2 = 0 + -49

Combine like terms: 49 + -49 = 0
0 + 7x + x2 = 0 + -49
7x + x2 = 0 + -49

Combine like terms: 0 + -49 = -49
7x + x2 = -49

The x term is 7x.  Take half its coefficient (3.5).
Square it (12.25) and add it to both sides.

Add '12.25' to each side of the equation.
7x + 12.25 + x2 = -49 + 12.25

Reorder the terms:
12.25 + 7x + x2 = -49 + 12.25

Combine like terms: -49 + 12.25 = -36.75
12.25 + 7x + x2 = -36.75

Factor a perfect square on the left side:
(x + 3.5)(x + 3.5) = -36.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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